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Mathematics
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Please help. Calculus
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\[ \int\limits x^3/\sqrt(x^2+36) dx \text(; ) x=6 \tan(\theta) \]
i guess you use \(x=6\tan(\theta) dx =6\sec^2\theta d\theta\)
I don't know how to sketch the triangle. I got the answer
|dw:1421448884886:dw|
\[x=6\tan(\theta), \tan(\theta)=\frac{x}{6}\]
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there is the picture of an angle whose tangent is x/6
Thank you. I dont have to put anything on the side of the triangle that has nothing written there
?
|dw:1421449416417:dw|
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