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PLEASE HELP! METAL. Find a cubic function with the given zeros. Square root of seven., -Square root of seven., -4 f(x) = x3 + 4x2+ 7x - 28 f(x) = x3 + 4x2 - 7x - 28 f(x) = x3 - 4x2 - 7x - 28 f(x) = x3 + 4x2 - 7x + 28
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\[(x+\sqrt7)(x-\sqrt7)=x^2-7\]
\[\sqrt{7},-\sqrt{7},- 4\]
multiply that happiness by \((x+4)\) and you will have your answer
yes.
i.e. \[(x+\sqrt7)(x-\sqrt7)(x+4)\] has the zeros you want then \[(x^2-7)(x+4)\] is all that is left to do
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if you are nervous about not getting the right answer use technology but it should not be too hard to do that multiplication
f(x) = x3 + 4x2 - 7x - 28?
yup
Lol, thanks.
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yw say hi to johnny for me
Ok.
how do you know johnny, that's my BF.
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