Question

prove sec(x)-1 / sec(x)+1 + cos(x)-1/cos(x)+1

Answer 1

i think you meant to say

\[\Large \frac{\sec(x)-1}{\sec(x)+1} = \frac{\cos(x)-1}{\cos(x)+1}\]

right?

Answer 2

you have + or = btw the two fractions?