Question

The measures of the sides of ΔPQR are given in the diagram. What is m∠P, correct to two decimal places?

Answer 1

you can use the law of cosines

\[QR ^{2}= PQ ^{2}+PR ^{2}-2(PQ)(PR)\cos P\]

Answer 2

you know the lengths QR, PQ, PR.

all you have to solve for is P

Answer 3

U can use the cosine rule to compute this
cos p = ((pq^2) + (pr^2) - (qr^2))/2.pq.pr
here we get ans 0.5974296454 rad