Question

HOW DO you solve sin ^2-tanxcos^ 2=0 on the interval

Answer 1

(sin(x))^2-tan(x)(cos(x))^2=0

Answer 2

tan(x)=sin(x)/cos(x)
sin(x)[sin(x)-cos(x)]=0

Answer 3

===> sin(x)=0 or sin(x)=cos(x)
sin(x)=0
x=asin(0)=0
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sin(x)=cos(x)=> x=45 deg