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Find the indicated function value if it exists, given f(x)=2-x and g(x)=sqrt 3-x (fog)(-2)
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\(\large\color{slate}{ fog }\) or \(\large\color{slate}{ f^\circ g }\) means \(\large\color{slate}{ f(\color{red}{g(x)}) }\)
2+2 and 3-2 i believe...right?
for(-2) would be \(\large\color{slate}{ f(\color{red}{g(-2)}) }\)
first find fog(x), then plug in -2 for x.
I mean fog(-2) would be \(\large\color{slate}{ f(\color{red}{g(-2)}) }\) in my 2nd reply, btw.
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\(\large\color{slate}{ f(\color{red}{g(x)}) =2-\color{red}{\sqrt{3-x}}}\) \(\large\color{slate}{ f(\color{red}{g(\color{blue}{-2})}) =2-\color{red}{\sqrt{3-(\color{blue}{-2})}}}\) find the \(\large\color{slate}{ f(\color{red}{g(\color{blue}{-2})})}\) .
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