Question

Simplify the expression

Answer 1

(cos^2x +sin^2x)/ (cot^2x -csc^2x)

Answer 2

Please help!!

Answer 3

ill try what grade r u in

Answer 4

11th this is pre-calc

Answer 5

wow im only in the 8th

Answer 6

\[\huge\color{green}{cos^2x + \sin^2x = ????}\]

Answer 7

Yes @Nnesha and then divided by the rest

Answer 8

\[\huge\color{purple}{{\rm cot^2}\rm x = ???}\]
change this also and then divide

Answer 9

cos^2x + sin^2 x = 1 right
so cot^2x = ??? can you tell me please :)

Answer 10

Oh I only know cot^2(x) + 1 = csc^2(x). Would that be the same thing?

Answer 11

okay subtract one both side then what you get ??

Answer 12

cot^2x=csc^2x-1

Answer 13

yes right so \[\huge\frac{ \cos^2x+\sin^2x }{ \cot^2x -\csc^2x }\]
\[\huge\frac{ 1 }{ \csc^2x-1-\csc^2x }\]
now solve this

Answer 14

\[\huge\color{blue}{{\rm csc^2x -}\rm \csc^2x = ???}\]

Answer 15

1

Answer 16

2-2 = ?? not one :)

Answer 17

oh lol sorry 0

Answer 18

lol yeah that's find :) :D

Answer 19

so what you have left ??

Answer 20

1?

Answer 21

nope

Answer 22

??????