Guys help!! I'll medal!!
Which is the solution set of x2 + 2x 8 > 0?
(Points : 1)
{x |4 < x < 2}
{x | 2 < x < 4}
{x | x < 4 or x > 2}
{x | x < 2 or x > 4}
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OpenStudy (anonymous):
Are you serious LEILA?
OpenStudy (anonymous):
I don't know how to do it..
OpenStudy (anonymous):
lol dw
Do you know how to factor?
OpenStudy (anonymous):
Yea
OpenStudy (anonymous):
Factor the equation. You should two binomials in the end.
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OpenStudy (anonymous):
Okay
OpenStudy (anonymous):
B?
Nnesha (nnesha):
2x ??? 8
positive 8 or negative 8 ??
OpenStudy (anonymous):
Just realized you're missing an operation
YEP NNESHA POINTED THAT OUT
Nnesha (nnesha):
yeah!! yaya :;)
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OpenStudy (anonymous):
Its -8
OpenStudy (anonymous):
Yeup makes sense now but it isn't B
Show me your binomial factors.
OpenStudy (anonymous):
x<−4 or x>2
Nnesha (nnesha):
*answer choices* signs are missing
who kidnapped *minus* signs ??
OpenStudy (anonymous):
MUST BE....the one they call...The Subtractor |_(0.0)_|
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Nnesha (nnesha):
:P
OpenStudy (anonymous):
Wait was I right?
OpenStudy (anonymous):
Leila, what choice is that for? That isn't B at all
OpenStudy (anonymous):
that's the only one that is x <4 though?
OpenStudy (anonymous):
There is one more.....staring righr at you...
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