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Mathematics 18 Online
OpenStudy (anonymous):

Guys help!! I'll medal!! Which is the solution set of x2 + 2x 8 > 0? (Points : 1) {x |4 < x < 2} {x | 2 < x < 4} {x | x < 4 or x > 2} {x | x < 2 or x > 4}

OpenStudy (anonymous):

Are you serious LEILA?

OpenStudy (anonymous):

I don't know how to do it..

OpenStudy (anonymous):

lol dw Do you know how to factor?

OpenStudy (anonymous):

Yea

OpenStudy (anonymous):

Factor the equation. You should two binomials in the end.

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

B?

Nnesha (nnesha):

2x ??? 8 positive 8 or negative 8 ??

OpenStudy (anonymous):

Just realized you're missing an operation YEP NNESHA POINTED THAT OUT

Nnesha (nnesha):

yeah!! yaya :;)

OpenStudy (anonymous):

Its -8

OpenStudy (anonymous):

Yeup makes sense now but it isn't B Show me your binomial factors.

OpenStudy (anonymous):

x<−4 or x>2

Nnesha (nnesha):

*answer choices* signs are missing who kidnapped *minus* signs ??

OpenStudy (anonymous):

MUST BE....the one they call...The Subtractor |_(0.0)_|

Nnesha (nnesha):

:P

OpenStudy (anonymous):

Wait was I right?

OpenStudy (anonymous):

Leila, what choice is that for? That isn't B at all

OpenStudy (anonymous):

that's the only one that is x <4 though?

OpenStudy (anonymous):

There is one more.....staring righr at you...

OpenStudy (anonymous):

my bad C

OpenStudy (anonymous):

Hallelujah

OpenStudy (anonymous):

Thank you lol

OpenStudy (anonymous):

No problem

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