1+cosx=2sin^2x Is there an identity I could substitute for?
do you know an identity for sin^2(x) that might be useful? check out the half identities under the half-angle identities http://www.purplemath.com/modules/idents.htm
oh wait are you solving an equation
or showing this is an identity or trying to show it isn't an identity
if this an equation you are solving just use sin^2(x)=1-cos^2(x)
Solving the equation
then write everything on one side and realize you have a quadratic in terms of cosine
do you see that or not see this so far?
\[\text{ Replace } sin^2(x) \text{ with } 1-cos^2(x) \\ 1+cos(x)=2(1-cos^2(x)) \\ \text{ put everything on one side } \\ 1+cos(x)-2(1-cos^2(x))=0 \\ \text{ distribute a little } \]
I don't see that
you don't see what?
the highest power is 2 and all the bases are cos(x)
so you have a quadratic in terms of cos
replace cos(x) with u might make it easier for you to see
\[1+u-2(1-u^2)=0\]
Oh okay then. I see what you're saying.
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