This is quick, can you just check my answer please!
What is y = x2 12x + 20 written in vertex form?
(Points : 4)
y = (x -12)^2 + 36
y = (x - 12)^2 + 26
y = (x- 6)^2 - 16
y = (x- 6)^2 + 20
I think it is C
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OpenStudy (anonymous):
Oops! the question is y=x^2 -12+20
OpenStudy (dtan5457):
x2 12x + 20
+/- 12x??
OpenStudy (dtan5457):
Oh nvm
OpenStudy (dtan5457):
y=x^2-12+20
Complete the square
y-20=x^2-12
(b/2)^2 for the value of c, which is 36, add to both sides
y+16=x^2-12+36
y+16=(x-6)^2
subtract 16
y=(x-6)^2-16
OpenStudy (anonymous):
Vertex form=y=a(x-h)^2+k
Find the vertex by x=(-b/2a)
x=6
Plug it in.
y=6^2-12(6)+20
y=36-72+20
y=-16
Vertex=(6,-16)
y=a(x+6)^2-16
So yeah, C is right.
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OpenStudy (dtan5457):
So yeah, you are right
OpenStudy (dtan5457):
epic timing @ashley_king
OpenStudy (anonymous):
ha i was just thinking that @dtan5457
OpenStudy (anonymous):
Haha thanks guys!! <3 :* Xx
OpenStudy (dtan5457):
We both have different ways of solving it though, good to look at both :)
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