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In triangle ABC, a = 3, b = 5, and c = 7. Find the measure of B. 22° 38° 142° 158°
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@perl
but itsn't that cheating?
its a way to check ?
no u can use calculators at school
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so its 38?
side A is opposite angle A
yes
thnx
you can use law of cosines by the way to solve this problem
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ok thnx
a = 3, b = 5, and c = 7. we want angle B , which is between sides a and c 3^2 + 7^2 - 2*3*7*cos(theta) = 5^2 solve for theta cos(theta) = (5^2 - 3^2 - 7^2)/(-2*3*7) theta = arcos(5^2 - 3^2 - 7^2)/(-2*3*7) theta = 38.2132
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