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The sides of an isosceles triangle are 5, 5, and 7. Find the measure of the vertex angle to the nearest degree.
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@perl
@luckycoins888
you can law of cosines
Let me get the equation started 5^2 + 5^2 - 2*5*5cos(theta) = 7^2
49?
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not quite, did you solve that?
5^2 + 5^2 - 2*5*5cos(theta) = 7^2 25 + 25 - 50 cos(theta) = 49 50 - 50*cos(theta) = 49 -50cos(theta) = 49 - 50 -50*cos(theta) = -1 cos(theta) = 1/50
thnx
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