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find f(-3) first
f(x)=2x so f(-3)=2(-3)=?
-6?
ok so we are asked to find |dw:1421794748870:dw|
we just found the inside part
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now we have to find g(-6) and we are done
g(x)=x^2+4 so g(-6)=?
i dont know
do you know how to replace the x's in g(x)=x^2+4 with 6's ?
-6's*
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because we are needing to find g(-6)
-32?
g(x)=x^2+4 g(-6)=(-6)^2+4 g(-6)=36+4=?
40
yes g(f(-3))=g(-6)=40
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\[g(f(x))=g(2x)=(2x)^2+4 =2^2 x^2+4 =4x^2+4 \\ g(f(-3))=4(-3)^2+4=4(9)+4=36+4=40\]
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