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Write an exponential equation in the form y=ab^x which graph passes through (-3,24) (-2,12) I think its 3(24)^x
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did you plug in the points into y=ab^x ? |dw:1421795479098:dw|
\[24=ab^{-3} \\ 12=ab^{-2}\]
this is a system of equations we have to solve
Like you could solve on of them for a in then use that in the other equation to solve for b
I didn't understand any of that. I figured it out. thanks though.
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\[25 =ab^{-3} \rightarrow 25b^{3}=ab^{-3}b^{3} \rightarrow 25b^3=ab^{0} \\ \rightarrow 25b^3=a(1) \rightarrow 25b^3=a\] see this first equation was solved for a
you are going to plug that into the other equation
and solve for b
you i got it already. thanks!
oops 25 is suppose to be 24
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