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Mathematics 18 Online
OpenStudy (loser66):

Calculus help!!, Someone explain me, please. Attachments on comment

OpenStudy (loser66):

OpenStudy (loser66):

At the end of the second attachment, I don't understand why \(f'(f^{-1}(x))(f^{-1}(x))'=1\)

OpenStudy (loser66):

@zepdrix @abb0t

OpenStudy (xapproachesinfinity):

just start with y=f(x) x=f^-1(y) do implicit diff you should achieve that result that gives us derivative of inverse functions

OpenStudy (xapproachesinfinity):

perhaps you are already familiar with that since you tool calc before

OpenStudy (loser66):

\(f(f^{-1}(x))=x\) hence derivative of it =1, understandable, but the last one is derivative of \(f^{-1}(x)\) , how can it =1?

OpenStudy (loser66):

You know what I mean?

OpenStudy (xapproachesinfinity):

hmm im looking at attachment..

OpenStudy (loser66):

|dw:1421803787081:dw|

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