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does anyone know how to graph this? My friend also needs to know the recursive and rule. Thanks for the help guysss :-)
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f(n+1)=s/3 f(n) f(0)=-3 s=? when n=0 f(n)=-3 f(n+1)=s/3f(n) f(0+1)=s/3*-3=-s f(1)=-s when n=1 f(1+1)=s/3*f(1)=s/3*(-s)=-s^2/3 etc
is that an "s" or a "5" kinda looks like a five
thanks @AJ01 !! my friend got it :) and that's a 5, thanks but she got it :))) @satellite73
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