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@ganeshie8
where are the options ?
a. 4 b. 4i c. 1+4i d -2i e 1-2i
set the equation equal to 0 and solve x
\[\large x^4 - 16 = 0\]
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\[\large (x^2)^2 - 4^2 = 0\]
\[\large (x^2-4)(x^2+4)= 0\]
so a?
nope
so its would be d or e e more because we need 2 +-
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