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thanks!!!!
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@ganeshie8
@Michele_Laino
Please note that if I add and subtract 16 at the left side of your equation, I get: \[x ^{2}+8x+16-16+13=5\] furthermore note that: \[x ^{2}+8x+16=(x+4)^{2}\] please continue
x=-4
please note that after the substitution, I get this: \[(x+4)^{2}-3=5\] and finally: \[(x+4)^{2}=8\] so, what is a?, What is b?
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a=8?
yes!
wait and b=18?
sorry b=8
haha and a=4 right?
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ok!
thanks so much!!!!!!!!!!!!
thanks!
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