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Mathematics 64 Online
OpenStudy (anonymous):

[5.05] DEFG is a rhombus. If EF = 10 and HF = 6, find EG. Rhombus D E F G is drawn with point H as the intersection of the diagonals. (3 points) 16 36 4 8

OpenStudy (anonymous):

OpenStudy (anonymous):

@iGreen

OpenStudy (igreen):

EG looks like a little more than double the length of HF..so what do you think is the answer?

OpenStudy (anonymous):

12

OpenStudy (anonymous):

right?

OpenStudy (igreen):

Yes, but that's not one of your options..so I'm thinking about the closest one to that..16.

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