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Multiply. (2n+2)(2n-2) @Jamesshe67
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differeeeence of sqrares
(a-b)*(a+b)=a^2-b^2
I got 4n^2-4
(2n+2)(2n-2)=4n^2-4
(2n+2)(2n-2) =(2n+2)(2n+-2) =(2n)(2n)+(2n)(-2)+(2)(2n)+(2)(-2) =4n2-4n+4n-4 =4n2-4
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Thank you guys so much!! @YOLO_KING @AlexandervonHumboldt2 @Jamesshe67 you guys down to help with some more ?:)
yup
Sure C:
Cool Cool!
yes can you medal me andd fan us
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C:^^^^
Yes but you guys all gave me answers so i have to do it fairly ;) Help me on the next ones and you will all get medals . promise!
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