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Absolute value of 2 - i?
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Maybe this will help. http://www.mathwarehouse.com/algebra/complex-number/absolute-value-complex-number.php
\[\sqrt{a^2+b^2}\] which in this case is \[\sqrt{2^2+1^2}\]
So 4?
HI!!
oh no dear it is not four!
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what is \(2^2+1^2\)?
oh my dear this is not supposed to be that hard what is two times two?
4
and one times one?
1
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and 4+1?
5
right final answer \(\sqrt5\) (not 16!!)
Thank you! I was putting way too much thought into it lol
\[\color\magenta\heartsuit\]
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