Question

x^2+8x+16=0... how many real solutions?

Answer 1

HI!!

Answer 2

you are supposed to recognize this at
\[(x+4)^2=0\]

Answer 3

so only one solution, namely \(x=-4\)

Answer 4

So one solution is all?

Answer 5

yes one solution x = 4

Answer 6

What about \[x^{2}\] -2x+3=0?

Answer 7

can also use this http://www.regentsprep.org/regents/math/algtrig/ate3/discriminant.htm

Answer 8

Can anybody help me with another?

Answer 9

leo this is on my test

Answer 10

lel

Answer 11

ok

Answer 12

i shall help