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OpenStudy (anonymous):
integrate from 9 to 1 (sqrt(u) - 2u^2)/ u DU not sure what to substitute in or how to start
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OpenStudy (freckles):
separate the fraction
OpenStudy (dumbcow):
\[\int\limits \frac{\sqrt{u} -2u^2}{u} = \int\limits u^{-1/2} - 2u\]
OpenStudy (solomonzelman):
came across... where are your du's ?
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