Question

Show that:

Answer 1

\[\frac{ \log_mx }{ \log _{mn}x}=1+\log_mn\]

Answer 2

@ganeshie8 @Miracrown

Answer 3

Take the left hand side and use change of base formula

Answer 4

what does it become?

Answer 5

do you know?

Answer 6

\[\log_ba = \dfrac{\ln ~a}{\ln~ b}\]

Answer 7

log m xlog mn x =1+log m n

Answer 8

I don't understand what to do with the base mn

Answer 9

@ganeshie8