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\(\sf \text{discriminant = b^2 - 4ac}\) if d=0, there is only one root. if d < 0, there's no real root. if d>0, there are two real roots
So the answer for 12 would be there's no real root? @Data_LG2
yes :)
and what about 11?
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apply the formula \(\sf \text{d = b^2 - 4ac}\), you just have to arrange the equation in the form \(\sf ax^2+bx+c=0\)
i mean \(\sf ay^2+by+c=0\) not x lol
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