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Help! Consider y = -2x^2+4x-1
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Solving for x, factoring?
1.) This equation is given in: (A) Standard form (B) Vertex form (C) Intercept form (D) No particular form 2.) This parabola opens: (A) upward (B) right (C) downward (D) left 3.) This parabola will have (A) a maximum (B) a minimum (C) neither a maximum or a minimum 4.) This axis of symmetry is (A) x=4 (B) x=-2 (C) x=1 (D) x=-1
My answers: 1.) A 2.) B 3.) B 4.) C
2 and 3 is incorrect
You got 1 and 4 correct
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consider ax^2+bx+c if a>0, it will open upwards if a<0, it will open downwards downwards parabola=maximum point upwards parabola=minimum point
So #2 is C, and #3 is A
yes
Thank you!(:
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