Question

verify (sec x - tan x)^2 = 1-cos x/1+cos x

Answer 1

which side do you want to start playing with?

Answer 2

\(\large\color{black}{ \displaystyle (\sec x - \tan x)^2=\frac{1-\cos x}{1+\cos x} }\)


playing with the left side
1. Multiply top and bottom times \(\large\color{black}{ \displaystyle 1-\cos x }\).
2. re-write the bottom in terms of sines, using \(\large\color{black}{ \sin^2x+\cos^2x=1 }\).
3. re-write each term in the fraction separately, simplifying as much as you can.
4. use the \(\large\color{black}{ a^2-2ab+b^2=(a+b)^2 }\).

Answer 3

Oh, this is playing with the right side, excuse me.

Answer 4

we can do a step at a time.

what do you get after doing step 1?