the vertex of this parabola is at (2, -4). When tge x-value is 3, the y-value is -1. What is the coefficient of the squared expression in the parabolas equation?
\({\huge\bf\color{red}\bigstar\color{orange}\bigstar\color{goldenrod}{\bigstar}\color{yellow}{\bigstar}\color{lightgreen}{\bigstar}\color{darkgreen}\bigstar\color{turquoise}{\bigstar}\color{royalblue}{\bigstar}\color{purple}{\bigstar}~\color{#00bfff}{\bigstar\bigstar\bigstar}\color{#11c520}{\bigstar\bigstar\bigstar}}\\{\huge\bf\color{red}W\color{orange}E\color{goldenrod}{L}\color{yellow}{C}\color{lightgreen}{O}\color{darkgreen}M\color{turquoise}{E~}\color{royalblue}{T}\color{purple}{O}~~\color{#00bfff}{Open}\color{#11c520}{Study}}\\{\huge\bf\color{red}\bigstar\color{orange}\bigstar\color{goldenrod}{\bigstar}\color{yellow}{\bigstar}\color{lightgreen}{\bigstar}\color{darkgreen}\bigstar\color{turquoise}{\bigstar}\color{royalblue}{\bigstar}\color{purple}{\bigstar}~\color{#00bfff}{\bigstar\bigstar\bigstar}\color{#11c520}{\bigstar\bigstar\bigstar}}\\\small\cal Made~by~@horsegirl27\)
\[y=a(x-h)^2+k \\ \text{ you are given } (h,k) \text{ is } (2,-4) \\ y=a(x-2)^2-4\] use the point given (3,-1) to find a
just replace x with 3 and y with -1 and solve for a
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