Question

The function h is defined by h(x)=3x-2 and the function g is defined by g(x)=3h(x)-1. If g(k)=11, what is the value of k?
A. 2
B. 3
C. 4
D. 5
E. 6

If k^4=16a^2, then k^2=
A. 4a^2
B. 1/4a
C. a/4
D. 4a
E. a^2/4

Answer 1

hm

Answer 2

g(x)=3h(x)-1
h(x)=3x-2

that means g(x) is actually 3(3x-2)-1

g(x)=6x-7

x= what to make g(x)= 11?

Answer 3

@dtan5457 ohhhhhh ty :D I made an error when somewhere

Answer 4

Wouldn't that be g(x)=9x-7 ??

Answer 5

oh crud

Answer 6

nvm I didn't make an error ... O.o

Answer 7

i guess i made an error too

Answer 8

lol

Answer 9

error or typo?

Answer 10

nvm i got it :D

Answer 11

actual error 3(3x) literally went to 6x in my mind for some reason

Answer 12

the answer is 4 ^.^

Answer 13

its been a long night ^_^

Answer 14

it's been a long but short life u.u

Answer 15

Why not 2 ??

Answer 16

9x-7

9(4)-7

36-7 if im not going crazy again is not 11

Answer 17

o.0 how did u get 2?

Answer 18

11 = 9x - 7

Answer 19

3(3x-2)(x)-1=11
9x-6(x)-1=11
9x-6x-1=11
3x-1=11
3x=12
x=4

Answer 20

maybe I erred also lol

Answer 21

ye

Answer 22

this can;t be real lol

Answer 23

wat can't ? @dtan5457

Answer 24

g(x)=3h(x)-1

is that 3(3x-2)-1?

Answer 25

h(x)=3x-2

Answer 26

?

Answer 27

there's also another x

Answer 28

3h(x)-1

Answer 29

Would not 3h(x) = 3(3x-2) where is the extra x coming from?

Answer 30

i'm pretty sure the x is part of the function name

Answer 31

not an extra x

Answer 32

function g is defined by g(x)=3h(x)-1

Answer 33

h(x) is the function name.

Answer 34

. _ . if i get it rong then whatever, but enuf w/ this qs. I'm pretty sure the other x is not part of the equation and the book this question is coming from isn't the best ._.

Answer 35

got it

Answer 36

@Nnesha ?

Answer 37

3(3x-2)(x)-1=11
^^^ how u got that x here ??

Answer 38

like radar sir said 11=9x-7
distribute then solve
isn't that right ??