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A projectile is fired from ground level with an initial speed of 250 m/sec and an angle of elevation of 30 degrees. Use that the acceleration due to gravity is 9.8 m/sec^2 The maximum height of the projectile is?
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I have r(t) = (125sqrt(3)t) i + (125t - 4.9t^2) j
i thought I would take d/dt (125t - 4.9t^2), then set to 0 and solve for t but that didn't work
;)
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