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I am trying to solve the following question. I would be extremely happy if you can provide me with some steps in solving this question. Many Thanks. Sketch the region bounded by the curves y=2square root of x, x+y=8 and y=1 then find the volume of the solid generated by revolving this region about the x-axis.
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Well, here's a rough sketch of the region.|dw:1422114043713:dw| Then you just need to do \[\int_0^8 \pi y^2 \, dx\]. You'll want to split into three integrals, though.
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