The plants in F1 (TTGG x ttGG) were allowed to undergo self-pollination. The expected phenotypic ratio to be obtained is? Show me how please :)
Hey there!
Hiiiii, please tell me you're familiar with this? :)
So the genotype of the parent plants are TTGG and ttGG Right?
yes
Yep, I am familiar (Thankfully ;))
So, first of all you know the meaning of self pollination ?
Because I have few more questions :p
I think
yes, yes, i do know
ok, now let's have a look real quick on how to work out a punnet square for this question.
well, yeah, that is the problem, i have no idea how to do it in this form. I know how to do for example TT X tt a monohybrid one :p
First of all we will have to find the F1 Generation. |dw:1422125372987:dw|
Yes, this one is Dihybrid Cross.
Next Step will be to self pollinate \(\sf F_1\) generation i.e. we will have to perform a cross between tTGG X tTGG
Getting it?
I think we have to perform a cross between TTGG x ttGG
We have to perform a self pollination on the \(\sf F_1\) generation, which will be given by TTGG X ttGG. The \(\sf F_1\) generation will be tTGG
Ahh, okay
|dw:1422125814529:dw|
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