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@iGreen
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@DanJS PLEASE HELP!
i got 0.55, right?
hi
\[\frac{ 1 }{ 3-1 }\int\limits_{1}^{3}\frac{ 1 }{ x }dx\]
is that it, i can't remember
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yeah it is..
The integral of 1/x is the natural log of absolute value of x... and at the lower bound, that is zero, so the integral evaluates to ln(3) overall half of natural log of 3
so the answer would be 1.10?
\[\frac{ \ln(3) }{ 2}\approx 0.55\] You had it right the first time..
Check this out, i found these the other day.
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ohhh thanks(:
thank you!!!
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