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Mathematics 7 Online
OpenStudy (anonymous):

Plz Help will give medal!! http://static.k12.com/calms_media/media/1357500_1358000/1357620/1/185dd4e634bcb63a38595f220e8901f867258840/MS_PHYS_SCI_286559.jpg What was the hiker's average velocity during part C of the hike? A. 10 km/h south west B. 0.10 km/h north C. 4.0 km/h south D. 6 km/h west

OpenStudy (anonymous):

Plz help

OpenStudy (godlovesme):

final distance- initial distance --> 6-0 over final time-initial time --> 10.45-9.45 6/1 = 6km/hr west :) @Dragonwiz88

OpenStudy (anonymous):

@Directrix & @Godlovesme

OpenStudy (anonymous):

oh

OpenStudy (godlovesme):

^^^ hopefully it's right lol i'm not confident

OpenStudy (anonymous):

So its D?

OpenStudy (godlovesme):

yes what do u think @Directrix

Directrix (directrix):

That is what I got. d/t = v 6 km w /1 hour = 6 km w per hour

OpenStudy (anonymous):

Im confused I had someone else tell me a which is it LOL

OpenStudy (anonymous):

A OR D

OpenStudy (godlovesme):

D @Dragonwiz88

OpenStudy (anonymous):

NVM I think its D

OpenStudy (anonymous):

ok thx

OpenStudy (godlovesme):

anytime :)

Directrix (directrix):

Maybe we are supposed to take into account the hiker's direction from the outset of the hike. On the other hand, how could his speed be anything other than 6?

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