Question

let me know if you see anything wrong with the way i am solving this i just find it easier to do on ops then copy and past to the doc so... yea

Answer 1

where is "The way I am solving"?

Answer 2

sin= opposite over hypotenuse
cos= adjacent over hypotenuse
tan= opposite over adjacent

csc= the exact opposite of sin
sec= exact opposite of cos
cot= exact opposite of tan

Answer 3

good

Answer 4

10 ADJ

Answer 5

But!! that is not \(\triangle ABC\)

Answer 6

work on one triangle at a time *

Answer 7

Cannot. must work 3triangles / time to get the answer. hehehe