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Mathematics 8 Online
OpenStudy (anonymous):

find the perimeter and area of the following composite shape.

OpenStudy (anonymous):

OpenStudy (alexandervonhumboldt2):

do you know how to find area of a semicircle and area of a rectangle?

OpenStudy (alexandervonhumboldt2):

area of a semicircle: 1/2*pi*r*r area of rectagngle: 20.2*3.1

OpenStudy (anonymous):

yeah i know the rectangle part, but not the semicircle part.

OpenStudy (alexandervonhumboldt2):

i told you the formula

OpenStudy (alexandervonhumboldt2):

so what is area of the semicircle?

OpenStudy (anonymous):

i dont know the radius..

OpenStudy (alexandervonhumboldt2):

20.2/2=10.1 is the radius

OpenStudy (alexandervonhumboldt2):

you know the diameter. radius is half the diameter

OpenStudy (anonymous):

okay, well give me a minute. dont leave lol.

OpenStudy (alexandervonhumboldt2):

ok

OpenStudy (alexandervonhumboldt2):

i'll help later with perimeter

OpenStudy (alexandervonhumboldt2):

lets finish with area

OpenStudy (anonymous):

do i add both areas of the shapes for the actual area?

OpenStudy (alexandervonhumboldt2):

yes

OpenStudy (alexandervonhumboldt2):

so for a semicircle area is 160.1557 for rectangle is 62.62

OpenStudy (alexandervonhumboldt2):

sso just add

OpenStudy (anonymous):

i got 382.9314?

OpenStudy (perl):

1/2* Pi * (20.2/2)^2 + 20.2*3.1

OpenStudy (anonymous):

can you like write it out? it could probably make me understand better.

OpenStudy (anonymous):

@perl

OpenStudy (alexandervonhumboldt2):

correct

OpenStudy (anonymous):

wait i was right? @AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

yeah

OpenStudy (anonymous):

are you positive cause its for a test grade?

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