Question

am i correct? @perl
Using the following equation, find the center and radius of the circle.
x^2-2x+y^2-6y=26
(x^2-2x)+(y^2-6y)=26
(x^2-2x+1)+(y^2-6y+9)=26+1+9
(x-1)^2+(y-3)^2=36
center is (1, 3) and radius is 6

Answer 1

@perl

Answer 2

ahh submited already forget now

Answer 3

i'm crazy asked if i'm correct and submited

Answer 4

phew