Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

y = four thirdsx + 8
y = four thirdsx + 3
y = -three fourthsx + 8
y = -three fourthsx + 3

Answer 1

@misty1212

Answer 2

you need the slope of \[4x-3y=-12\] the slope of
\[ax+by=c\] is \[m=-\frac{a}{b}\]

Answer 3

okso the slope is 4/3 @misty1212

Answer 4

yes

Answer 5

now
\[y-4=\frac{4}{3}(x+3)\] solve for \(y\)

Answer 6

ok y-4+4 =4/3x +4+4

Answer 7

the answer is a @misty1212 right

Answer 8

it is correct when you write
\[y=\frac{4}{3}x+8\]

Answer 9

so that is the answer a???

Answer 10

@misty1212

Answer 11

lol yeah