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need help simplifying
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16x^2-4x/4x
\[\frac{ 16x^2-4x }{ 4x }\]
take 4x common from numerator. It will cancel with the denominator and bingo!
can u show me how its done
just divde 4x with 16x^2 and 4x
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is my answer |dw:1422255484021:dw|
\[4x(x-1)\div4x\] Cancel the 4x in numerator and denominator and you're left with x-1
|dw:1422255539614:dw|
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