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Invert \(2e^x-\frac{1}{e^x}\).
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Inverse of \(2y-\frac{1}{y}\).
okay suppose X=2y-1/y
oh u make e^x=y
and no need for that stuff
just say y=2*e^x - 1/e^x solve for x in terms of y
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I know that but what are the steps? Wolfram Alpha gives \(\log\left(\frac{1}{4}(x-\sqrt{x^2+8}\right)\) but I have no idea where that came from.
okay
lets work it out
actually im more comfortable with the substitution u = e^x
hmm
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