Question

2(tan)^2 45 degrees - 3 tan 60 deg. + cot 30 deg. + 1 will fan and medal

Answer 1

so if substituted,

2 (1)^2 - 3 (sqr. of 3) + sqr. of 3 + 1

Answer 2

\[2\tan^2(45^\circ)-3\tan(60^\circ)+\cot(30^\circ)+1?\]

Answer 3

yep

Answer 4

Simplify?

Answer 5

yeah

Answer 6

\[
2(1)^2-3\sqrt{3}+\sqrt{3}+1=3-2\sqrt{3}
\]
I think the answer in this form should be okay