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F(x)=2x+1 and g(x)=(3x-1)/(2) g(f(3))
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g(f(x) means that you have to fill in the f(x) function for every x in g(x) function
so g(f(x)) will become -> (3(2x+1))/(2) -> (6x+3)/(2) g(f(3)) means you fill 3 in for all x's in that new fused function so -> (6*3+3)/(2)=21/2
thanks
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