What is the slope-intercept form of the function that contains the point (–1, 5) and has a slope of –4? y = x +
@SolomonZelman
\(\large\color{slate}{ \displaystyle y-y_{_{^1}}= m\left( x-x_{_{^1}} \right) }\)
Where, \(\large\color{blue}{ \displaystyle \left(x_{_{^1}},y_{_{^1}} \right) }\) is the point and \(\large\color{blue}{ \displaystyle m }\) is the slope.
so m=-4
yes.
can you fill in the \(\large\color{slate}{ \displaystyle y-y_{_{^1}}= m\left( x-x_{_{^1}} \right) }\) ?
is it y=-1x+5
@satellite73 may you help me please
\(\large\color{slate}{ \displaystyle y-y_{_{^1}}= m\left( x-x_{_{^1}} \right) }\) \(\large\color{slate}{ \displaystyle y-(5)= -4\left( x-(-1)\right) }\)
you need to convert to: \(\large\color{slate}{ y=mx+b }\) that is all.
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