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solve each system using substitution. check your answer. y=8-x 7=2-y
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maybe you meant: \(\normalsize\color{royalblue}{ \rm y=8-x }\) \(\normalsize\color{royalblue}{ \rm x=2-y }\) ???
no thats how it is
\(\normalsize\color{royalblue}{ \rm y=8-x }\) \(\normalsize\color{royalblue}{ \rm 7=2-y }\) solve for y, in equation 2. Substitute your y solution into the first equation. solve for x in the (new formed) first equation
Solve for one of the variables first. Im going to solve for y in the bottom first. Using the subtraction and multiplication properties of equality. You'll get that y= -5. Substitute that into the first one and solve for x.
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