Question

alg2 help 7/3x + 2/x+ x/x-1

Answer 1

so are we simplifying?

Answer 2

I simplified it a little bit.

Answer 3

7/3x+6/3x+x/x-1

Answer 4

For the last one, I am not sure what denominator we should use. Anyone ?

Answer 5

how do I find the denominator

Answer 6

That is what I am confused about ?

Answer 7

\[\huge \frac{7}{3x}+\frac{2}{x}+\frac{x}{x-1}\]??

Answer 8

common denominator would be
\[3x(x-1)\] if that is the question

Answer 9

ladystar. send us a screen shot of the question

Answer 10

misty has it but how do I find the denominator

Answer 11

i wrote it
it is\[\huge 3x(x-1)\]

Answer 12

\[ \frac{7}{3x}+\frac{2}{x}+\frac{x}{x-1}\]\[\frac{7}{3x}\times \frac{x-1}{x-1}+\frac{2}{x}\times\frac{ 3(x-1)}{3(x-1)}+\frac{x}{x-1}\times \frac{3x}{3x}\]\]