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asap medal!! solve 2 sin^2x-sin x=0 for principal values of x.
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\[\sin(x)(2\sin(x)-1)=0\] is a start
that makes \[\sin(x)=0\\ \sin(x)=\frac{1}{2}\]
is this right
@cutegirl That is not what I got.
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that was my other chioce
And of @hartnn and @Shanaronan http://openstudy.com/updates/52d17cbbe4b00c91d586a2d0
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