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Mathematics 19 Online
OpenStudy (anonymous):

asap medal!! solve 2 sin^2x-sin x=0 for principal values of x.

OpenStudy (anonymous):

OpenStudy (misty1212):

\[\sin(x)(2\sin(x)-1)=0\] is a start

OpenStudy (misty1212):

that makes \[\sin(x)=0\\ \sin(x)=\frac{1}{2}\]

OpenStudy (anonymous):

is this right

Directrix (directrix):

@cutegirl That is not what I got.

OpenStudy (anonymous):

that was my other chioce

Directrix (directrix):

And of @hartnn and @Shanaronan http://openstudy.com/updates/52d17cbbe4b00c91d586a2d0

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