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solve 2 cos x-1=0 for 0 <= x< 2 pi
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this one should be easy haha
\[\cos x-1=0 \Longrightarrow \cos x=1 \Longrightarrow x=0\]
oh you have 2cosx my bad hehe didn't see 2
its all good
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\[2\cos x-1=0 ==> \cos x=\frac{1}{2}\] so \[x=\frac{\pi}{3}, \frac{5\pi}{3}\]
thanks so much
wlc!
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