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OpenStudy (smurfy14):
Please help me before I rip my hair out! Show that P(A∪B ∪C) = P(A) + P(Ac ∩B) + P(Ac ∩Bc ∩C). Treat B∪C as one set first. You will also need to use (S∪T)∩U = (S∩U)∪(T ∩U)
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