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AP statistics... Was wondering if someone could review my homework answers. Thanks!
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1) D 2) A
@ganeshie8 was wondering if u could review my homework answers..
@Preetha
this is a valid probability distribution since the probabilities add up to 1 1) expected value (mu) is equal to sum x * P(x) 4*1/3 + 3*1/12 + 2*7/12 = 2.75
the variance should be .92
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