Question

Evaluate cot 45° without using a calculator by using ratios in a reference triangle.

Answer 1

hint: \(\bf cot(\theta)=\cfrac{adjacent}{opposite}=\cfrac{y}{x}=\cfrac{{\color{blue}{ cos}}(\theta)}{{\color{brown}{ sin}}(\theta)}\qquad thus
\\ \quad \\
cot(45^o)=\cfrac{adjacent}{opposite}=\cfrac{y}{x}=\cfrac{{\color{blue}{ cos}}(45^o)}{{\color{brown}{ sin}}(45^o)}\)

Answer 2

thanks jdoe0001

Answer 3

yw